$\frac{2x^3+19,25x^2-3x+8}{x-2}$
$\lim_{x\to0}\left(\frac{3x^5+6x^2}{4x^3+2}\right)$
$6^2\cdot7^2$
$9x^2-4x-\left(3x-2\right)^2$
$3x^2-34x+70\ge0$
$\frac{5}{4.83}$
$\frac{2x^4+3x^3-6x^2+7}{-1}$
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