$\frac{d}{dx}\left(x\left(x-3\right)\left(x+2\right)\right)$
$\int\frac{6x+2}{\left(2x+1\right)\left(x^2+3\right)}dx$
$2a+3b-7=15$
$\left(m^3+a^n\right)^5$
$18y^3+14y^2-4y$
$\frac{dy}{dx}=\frac{2x^3+2-x}{2x^2}$
$20+90+515mn7$
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