$\frac{3x^3-20x^2+37x-20}{x-4}$
$\lim_{x\to\infty}\left(\frac{x+1}{x^2+4x+3}\right)$
$\sqrt{3+\sqrt{8+5x}}=\sqrt{2x-1}$
$16x^4-y^8$
$2045-2045+1915$
$x^2-2x=-x^2-24x-144$
$2,4\:\le400\:=x$
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