$\left(3x^3-24x^2+48x\right)^2$
$2x+7\le4-x$
$\sqrt{1+x^2}\left(\frac{dy}{dx}\right)=\frac{x}{y}\:\:\:\:\:\:y\left(0\right)=-3$
$y\frac{2x}{x^2-4}$
$m^3+4m^2+4m$
$5\left(2s+7\right)+6s$
$-10.7+-3.5$
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