$\lim_{x\to\infty}\left(\frac{x^2-7x+4}{x-3}\right)^{\frac{x+1}{x-7}}$
$x+14=3$
$3x+7=13$
$12x-4\:3x+1$
$\int\:\frac{7}{4}x^2dx$
$\lim_{x\to0}\left(\frac{8^t-5^t}{t}\right)$
$6a^{8}b^{8}\quad3a^{5}b^{2}$
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