$$43\cdot\left(-33-45\right)$$

$$\lim_{x\to\infty}\left(\frac{3x^3-6x^2+3x+6}{-3x^2+4x-4}\right)$$

$$9u+4u$$

$$\int\left(-3x\right)\left(3^{2x}\right)dx$$

$$\left(2a^2b+5\right)\left(2a^2b-5\right)$$

$$\left(x\:+\:7\right)^4$$

$$\frac{x^3+6x^2+5x+1}{x-1}$$