$\frac{x_{-3}}{2}-\frac{x-2}{8}\le\frac{x}{2}$
$m^2-12m+11$
$\frac{\left(\frac{a}{b}+1\right)}{\frac{b}{a}-1}$
$-8+\frac{16}{8}+-4\left(-3\right)^2$
$x^5-6x^3+6x^2-7x+6$
$\int\frac{\left(2r\right)}{\left(1-r\right)^7}dr$
$\frac{7^{2m}}{49^m}=7^{2m-2m}$
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