$\frac{x^2}{4}-\frac{xy}{3}-\frac{y^2}{9}$
$\frac{1}{25-sin^2x}$
$5\cdot\left(-12\right)\cdot\left(-3\right)$
$8+16x^2$
$\left(\:+0\right)-\:\left(+8\right)$
$4x^2-13x+13>0$
$x^2+5x\:+\:121$
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