$\int\frac{1}{\sqrt{y}-y}dy$
$g\left(x\right)=\left(4x-3\right)^2$
$0\cdot0+2$
$3x^2>-343$
$\int\left(\frac{4}{\sqrt[3]{3+6x}}\right)dx$
$\frac{x+6}{4x^2}+\frac{3}{2x^2}=\frac{x+2}{2x^2}$
$ctg^2x\left(1-cos2x\right)+sen^2x=2$
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