$\lim_{x\to\infty}\frac{5x+9}{8x^2-3x+11}$
$\lim_{x\to0}\left(\frac{x^3+4x^2-16x-64}{x^2-4}\right)$
$-25\:+\:\left(-6\right)\:-\:\left(-1\right)\:$
$\left(4a^2+b\right)^2$
$16x^2+48+36$
$\int\frac{\left(3x-2\right)}{\left(3x^2-4x+7\right)}dx$
$14\cdot7.50$
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