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Exercise

$2x\sin x^2$

Step-by-step Solution

1

Applying the trigonometric identity: $\sin\left(\theta \right)^2 = 1-\cos\left(\theta \right)^2$

$2x\left(1-\cos\left(x\right)^2\right)$
Why is 1 - cos(x)^2 = sin(x)^2 ?
2

Solve the product $2x\left(1-\cos\left(x\right)^2\right)$

$x2\cdot 1+2\cdot -\cos\left(x\right)^2$
3

Any expression multiplied by $1$ is equal to itself

$x2+2\cdot -\cos\left(x\right)^2$
4

Multiply $2$ times $-1$

$x2-2\cos\left(x\right)^2$

Final answer to the exercise

$x2-2\cos\left(x\right)^2$

Try other ways to solve this exercise

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$a+2a+9a$

Main Topic: Equivalent Expressions

Two algebraic expressions are equivalent if they stay equal to each other, for any values their variables can take.

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