$\pi\frac{5}{6}^2\cdot\frac{16}{5}$
$\frac{\left(\frac{1}{x}-\frac{1}{5}\right)}{x-5}$
$16\left(6x-12\right)+36$
$\frac{1}{y^2}y'\:=-2x$
$\lim_{x\to-\infty}\left(-3x^3+5x^2-10\right)$
$x^3-3^2-2x+1$
$tan^2\theta\:\:csc^2\theta\:\:cot^2\theta\:\:sin^2\theta=1$
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