$-x^2\left(4x^2-1\right)$
$-\frac{1}{4}+\frac{13}{4}$
$\lim_{x\to2}\frac{\left(x^2+x-6\right)}{x-2}$
$2x-40>50x+16$
$\frac{m^9-n^9}{m+n}$
$3.8\cdot10^4$
$5^2x\:5^2$
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