$10x-4+9+3x$
$19-\left(-12\right)$
$\frac{d}{dx}3y-x^2=\sqrt{xy}$
$3j+10\le1$
$\frac{2x^2y^{-2}}{2y}$
$\int\frac{12x-4}{x\left(2x-1\right)^2}dx$
$\frac{1}{3}\frac{dy}{dx}-y=1$
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