$3x\:+\:5\:\le\:-7x\:-\:8$
$8x^3-4$
$\frac{2x^3-5x}{x-3}$
$\frac{e^{-x^3}}{x^3}$
$8cos\left(3x\right)=6$
$\frac{10x^4-15x^3}{5x^2}$
$\lim_{x\to\infty}\ln\left(\frac{4e^{2x}}{16e^{4x}}\right)$
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