$5\:-\:2x\:+\:x$
$\int_{2c}^{4c}\left(\frac{1}{\sqrt{x^2-4c^2}}\right)dx$
$\log_{5x}\left(25\right)=1$
$\frac{x^2-4y^2}{x\:-\:2y}$
$\frac{9\cdot81\cdot0.037}{81\cdot0.004}$
$\frac{1}{2y-1}y'=-x^2$
$\sqrt{2-2cos\left(4x\right)}$
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