$14.52x\frac{1}{2}$
$3\left(t-4\right)+6=3\left(2t-4\right)$
$n^2-16$
$6x^2+3a^2=12$
$\left|5x+\left(2x\right)^2\right|^2$
$\frac{x^2-16}{x+3}+\frac{1}{x+4}$
$63\le-4x-17$
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