$5x-3\left(x-4\right)$
$\int\left(8\left(2x-3\right)^2\right)dx$
$4x^2+2x^2-x$
$\frac{x}{x-2}=\frac{2}{x+4}-\frac{2x}{x^2+2x-8}$
$\frac{5}{6}a^2-\frac{5}{12}a^2b$
$\sqrt{\left(x+7\right)\cdot\left(x-3\right)}$
$\lim_{x\to\infty}\sqrt{10x^2-4x^2}-\sqrt{10x^2-6x}$
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