$\int x^2\:cot^{-1}\left(3x\right)dx$

$\left(\sqrt[2]{7y}\right)^3$

$\left(h-9\right)^3$

$x=\frac{\left(n+1\right)^2\left(\left(n+1\right)^4-1\right)}{n^2\left(n^4-1\right)}$

$\int_{-\infty\:}^9\left(\frac{1}{2x-5}\right)dx$

$-4\ge-6s-8$

$\int\left(6x+2\right)\left(3x^2+2x\right)dx$