$4x^2-16y^2$
$\int\left(\frac{8x}{5+4x^2}\right)dx$
$\int_0^{\frac{\pi}{2}}\left(11\cos\left(12x\right)\cos\left(13x\right)\right)dx$
$6+6>12$
$\left(-26\right)\cdot\left(-72\right)$
$x^2+8x-8x-64$
$\sqrt{-11}$
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