$2\left(-2\right)^4-32$
$\left(4xy-2z\right)^3$
$06,489+51.400$
$\lim_{x\to\infty}\left(\frac{\tan\left(x\right)-\sin\left(x\right)}{x^3}\right)$
$a^2-14a+48$
$\frac{\left(\frac{1}{3}z^5\right)}{\left(-\frac{1}{27}z^3\right)}$
$\frac{dy}{dx}=\frac{2x}{x^2+3x+2}$
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