(20 − 18 : 2)\left(20\:-\:18\::\:2\right)(20−18:2)
e−y(1+dydx)=0e^{-y}\left(1+\frac{dy}{dx}\right)=0e−y(1+dxdy)=0
c7c−1\frac{c^7}{c^{-1}}c−1c7
−72.21\frac{-7}{2}.\frac{2}{1}2−7.12
∫5(4−2x)2dx\int\frac{5}{\left(4-2x\right)^2}dx∫(4−2x)25dx
(2−y)dy=x dx\left(2-y\right)dy=x\:dx(2−y)dy=xdx
∫1y2xdx\int_1^{y^2}xdx∫1y2xdx
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