$3y^5+6y^5$
$-3x^2-\:3x^2-3x^2$
$3y^2-33y+54$
$\frac{dy}{dx\:}=\:\frac{\left(-8\right)}{\left(4x+7\right)^3}$
$3\left(4x^2-2x\right)-2\left(3x^2+x\right)$
$z'-3yz=-1$
$-3x^2y+12xy^2$
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