$\left(\frac{4x^5y}{16xy^4}\right)^3$
$\int_1^4\left(\frac{x}{x^2-4}\right)dx$
$x^2-8x+4^2$
$2x+x-2+3x-3$
$\lim_{x\to\infty}\left(\frac{x^2+2x+4}{3x+2}\right)^3$
$\lim_{x\to0}\left(5x+4\right)$
$\int xe^{\left(-2x\right)}dt$
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