$\frac{1}{3}x=9$
$9x^4+16y^4+24x^2y^2$
$\sqrt[3]{27x^6y^4z^8}$
$f\left(x\right)=\frac{5x^8-x^7}{2x^8+2}$
$\frac{\sqrt[5]{3^3}.\:5^2.11^4}{19}$
$-2x+4\le3x+8$
$\int\frac{4x^2-19x+12}{x\left(x-2\right)^2}dx$
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