$\frac{z^2+z+3}{z^3+2z^3+z+5}$
$\sin\left(x\right)\cot\left(x\right)=-\frac{1}{4}$
$\log\left(3x-3\right)=\log\left(x+1\right)+\log\left(4\right)$
$\lim_{x\to\infty}\:\frac{\left(1+x^2\right)}{\left(1-x^2\right)}$
$\sqrt{1.9^2}$
$\csc x^2-\csc x=0$
$n^3\:=\:64$
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