$\lim_{x\to\infty}\left(\frac{\left(2-n\right)\left(n+2\right)}{n}\right)$
$\left(-1\right)^n\frac{2}{3^{n+1}}x^{n+1}$
$\frac{x^2-4^2}{x+2}$
$2x^4+9y=2x^2y+36$
$-5\cdot3\left(\left(-4-2\right)\right)$
$3ab-4bc-5ab+6bc$
$\left(x+4\right)\left(x-6\right)\left(x-31\right)$
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