$\lim_{x\to-1}\left(\frac{3x^3-x^2}{2x+1}\right)$
$4\left(6x-6\right)+4\left(-2x+9\right)$
$x''-x'=0$
$4x\\:+\\:9-3x-x$
$y-3x=5$
$\frac{x-4}{x+3}\le o$
$\left(-11\right)+\left(+8\right)-\left(-6\right)$
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