$\frac{x^2+1}{x^2-1}$
$\left(\frac{1}{cosx}-tanx\right)^2=\:\frac{1-sinx}{1+sinx}$
$-2.4\left(2x-2.1\right)$
$\frac{9c}{2}=\frac{4c}{3}$
$\frac{\sin\left(2x\right)}{4\sin\left(2x\right)-1}=1$
$\csc\left(x\right)=-4$
$\left(2x+8\right)\left(x+2\right)$
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