13(x−12)−4x\frac{1}{3}\left(x-12\right)-4x31(x−12)−4x
x2=8x+15x^2=8x+15x2=8x+15
8+4−6+14−12+15−498+4-6+14-12+15-498+4−6+14−12+15−49
limx→0(8inx2x2−1)\lim_{x\to0}\left(\frac{8inx^2}{x^2-1}\right)x→0lim(x2−18inx2)
y′+y=8xexy'+y=8xe^xy′+y=8xex
2x2−62x2−9\frac{2x^2-6}{2x^2-9}2x2−92x2−6
∫(e−2x8+e−2x)dx\int\left(\frac{e^{-2x}}{8+e^{-2x}}\right)dx∫(8+e−2xe−2x)dx
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