$16x^2+40xy^2+25y^4$

$\left(x^2+y^3-8\right)\left(8+x^2y^3\right)$

$2\:\ln\left(x\right)-\ln\left(5\right)=\ln\left(x+10\right)$

$\left(4b^5+15\right)\left(4b^5-12\right)$

$\left(8\right)-\left(-7\right)$

$\lim_{x\to0}\left(e^{3x}-3x\right)^{\frac{1}{x}}$

$\left(4t^3+5u^2\right)^2$