$\lim_{x\to0}\left(ln\left|x\right|-ln\left|x\right|\right)$
$x-\left(x^6\cdot e^x+4y\right)y'=0$
$\frac{-12x^3+9x^2+20x+15}{-4x+3}$
$6\cdot2-x-12\frac{12x^3}{6x^{-2}}$
$4+x=\left(4-2x\right)\cdot2+6$
$\lim_{x\to1}\left(\frac{1}{x-1}\right)^{\ln\left(x\right)}$
$2x^2\:-\:6x\:+\:3\:=\:0$
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