$25x^2+80xy+64x^2$
$\frac{d}{dx}arc\:cot\:2x^4$
$\frac{d}{dx}\left(\sqrt[3]{\frac{\sqrt[3]{x}}{\left(2x-1\right)^3}}\right)$
$2x^5-4x$
$\left(-16x^{17}+4x^{18}-7x\right)\left(6x^2y\right)$
$\frac{d^2}{dx^2}\left(f^3\left(x\right)\right)$
$x^3=x$
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