$6\sqrt{2x}\cdot4\sqrt[3]{3x^2y}$
$2-3\:\left|-2^3-\left(-8+7\right)^3-5\right|$
$\lim_{n\to\infty}\left(\frac{\left(n^2-1\right)^7}{n^k}\right)$
$\frac{x^2+3x-2}{x+1}$
$100y^2-100y+25$
$\left(6w^5\right)^2$
$\frac{x^2+1}{x}\ge1$
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