$\frac{\left(x-1\right)^2}{x^2-1}$
$3x+1>x+9$
$4x-6$
$\lim_{x\to0}\frac{2^x-7^x}{x^4-x}$
$\sqrt{6-4}$
$\frac{d}{dx}\left(ln\left(x+\sqrt{x^2+k}\right)\right)$
$2a^3-2a^2\:b+2b^3,3a^2\:b-4ab^2-4b^3,2ab^2-a^{\left(3.\right)}$
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