$\frac{dy}{dx}=\frac{3x^2+5x}{4y^3}$
$m^y\cdot m$
$\left(3x^4+2\right)^2$
$5x\cdot563+46x$
$\left(3x^5y\right)^5$
$\int\left(\frac{1}{18-5x}\right)dx$
$x^3+y^3=8$
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