$2700e^{0.08\left(8\right)}$
$x^2\le3-2x$
$\lim_{x\to\infty}\left(\frac{x+3x-4}{x-3x+2}\right)$
$f\left(x\right)=\left(4b^2-b\right)\left(b^3-8b^2+12\right)$
$\frac{dy}{dx}=-10y+10$
$\frac{1}{1+tan^2}\:=\:cos^2$
$v-10=-3$
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