$\frac{dy}{dx}=\frac{\left(2y^2+9x\right)}{2xy}$

$\lim_{x\to0}\left(\frac{\arctan\left(ax\right)}{8x^3}\right)$

$16-3\left(4-6\right)$

$\frac{dy}{dx}=\frac{\left(4x+xy^2\right)}{y+x^2y}$

$-9.98x\:-\:1.08x$

$\int ( 2 x - 3 ) ^ { 3 } d x$

$\lim_{x\to\frac{\pi}{2}}\left(\cos\left(x\right)\right)^{\frac{1}{x}}$