$\int e^{\left(x-4\right)}dx$
$\frac{170}{17}$
$\lim_{x\to\infty}x\ln\left(\frac{x-4}{x+2}\right)$
$4\left(x^2-6x+9\right)$
$\left(\frac{x^2}{\sqrt{\:3}}\:+\frac{\:3}{\:x^{\:4}}\right)$
$\left(-10\right)^3\left(10\right)^{-3}$
$4x^8-9$
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