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Exercise

2π∫01(g3)9g2+4dg2\pi\int_0^1\left(g^3\right)\sqrt{9g^2+4}dg

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Final answer to the exercise

214748364721474836472147483647(13)5−10553221.7011218⋅(214748364721257404.5846147)2147483647+8(70255.5690623679277.4065816)−70255.5690623679277.4065816(13)3\frac{2147483647\frac{2147483647}{2147483647}\sqrt{\left(13\right)^{5}}-10553221.7011218\cdot \left(\frac{2147483647}{21257404.5846147}\right)}{2147483647}+8\left(\frac{70255.5690623}{679277.4065816}\right)-\frac{70255.5690623}{679277.4065816}\sqrt{\left(13\right)^{3}}

Exact Numeric Answer

4.9364184.936418

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2π∫01(g3)√9g2+4dg
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