limt→∞(1+(3t))t\lim_{t\to\infty}\left(1+\left(\frac{3}{t}\right)\right)^tt→∞lim(1+(t3))t
(a−2b−5c)2\left(a-2b-5c\right)^2(a−2b−5c)2
∫x−1x2(x2+1)dx\int\frac{x-1}{x^2\left(x^2+1\right)}dx∫x2(x2+1)x−1dx
2x+1≥x+52x+1\ge x+52x+1≥x+5
2x+2y−∣x−(x−y)∣2x+2y-\left|x-\left(x-y\right)\right|2x+2y−∣x−(x−y)∣
3x+4−5x−3+7x3x+4-5x-3+7x3x+4−5x−3+7x
36x2\frac{3}{6x^2}6x23
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