$\frac{2x^2-x-6}{x+3}-2=\frac{2-x}{2}$

$\lim_{x\to\frac{\pi}{4}}\left(-\left(tan\left(x\right)-1\right)sec\left(2\cdot x\right)\right)$

$\lim_{x\to0}\left(x^2\right)\ln\left(x\right)^2$

$f\left(x\right)=x^3+2x$

$\frac{dx}{du}=\frac{\left(1-3u\right)x}{u}=3$

$3.4\cdot10^{-6}+2.4\cdot10^{-6}x$

$3y^3+x^2=5$