$7\left(3x+7\right)-3x+1$
$\frac{dy}{dx}=\frac{1}{6}\left(100-y\right)$
$f\left(x\right)=\left(x^3-x\right)^3$
$x-5=13$
$3x^2-48x+256=0$
$49-\left(-16\right)$
$\left(0.2x^6-1.3y^6\right)^2$
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