$\int\left(6t^2e^{6t^3}\right)dt$
$4\:+\:\left(-3\right)+\:8\:-\:\left(-9\right)$
$3-4x^2+x^4-2x^3+3x-x^2$
$9x^2-72=0$
$\left(6x+3y\right)^5$
$x^4+5x^2+9$
$\frac{d}{dx}\left(\left(x+1\right)^2\left(x^2+1\right)^{-3}=y\right)$
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