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Exercise

2csc⁡(x)−3(sec⁡(x)−cot⁡(x))+4tan⁡(x)2\csc\left(x\right)-3\left(\sec\left(x\right)-\cot\left(x\right)\right)+4\tan\left(x\right)

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Final answer to the exercise

2cos⁡(x)+3cos⁡(x)2−3sec⁡(x)sin⁡(x)cos⁡(x)+4sin⁡(x)2sin⁡(x)cos⁡(x)\frac{2\cos\left(x\right)+3\cos\left(x\right)^2-3\sec\left(x\right)\sin\left(x\right)\cos\left(x\right)+4\sin\left(x\right)^2}{\sin\left(x\right)\cos\left(x\right)}

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2csc(x)−3(sec(x)−cot(x))+4tan(x)
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