$\lim_{x\to-6}\frac{x-3}{x+6}$
$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left(secx\:+\:tgx\:-\:1\right)\:\left(secx\:-\:tgx\:+\:1\right)$
$\int\left(6\sin\left(x\right)\cos\left(2x\right)\right)dx$
$\frac{2}{3}h-\frac{1}{3}h+11=8$
$10+1-9+3+1$
$-x+2y-5+x-3y+5$
$y^2-6y+4$
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