$169\:-\:z^2$
$\left(12x^3-5\right)^4$
$\int\frac{z}{\left(z-1\right)^3}dz$
$\lim_{x\to\infty}\:\frac{ln4}{ln8}$
$\lim_{x\to0}\left(\frac{\left(x+2\right)}{e^x}\right)$
$3m=12$
$\frac{3x-4}{5}\cdot20$
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