$-5\cdot\left|1\right|-3\cdot\left|1\right|^2+\left(7\left|-1\right|^2\left|1\right|^3\right)$
$\int\frac{\left(2x+1\right)}{\left(x^2-6x+13\right)}dx$
$\left(5a^5+4b^2\:\right)\left(5a^5-4b^2\:\right)$
$x^2+4y^2-8x-48y+156=0$
$3x^2+9x\le0$
$\frac{dy}{dx}=3xf^2$
$12+4+2-13-24-2+3-2$
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