$\int ke^{2t}dt$
$\left(3y\:5\:\right)\left(5y\:4\:\right)$
$-1=\frac{x}{5}-3$
$\left(x^{3}+7x^{2}+7x-5\right):\left(-x^{2}-x+2\right)$
$\left(y^3+2z\right)^2$
$\frac{tan\left(67.5\right)}{1-tan^2\left(67.5\right)}$
$5\cdot3^{\left(-n-1\right)}$
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