$\frac{dy}{dx}=\left(y+1\right)^{-3}$

$\lim_{x\to1}\left(\frac{\sin\left(x\right)}{x+3x^2}\right)$

$\left(4u-8+3v\right)\left(4u+5v-8\right)$

$\frac{4x-5}{\left(x^3-x^2-5x-3\right)}$

$y=\frac{\left(x^3-2x\right)}{\left(5x+2\right)}$

$\int\frac{1}{\left(4x^2-25\right)}dx$

$\left(25\cdot0.11111111111111\right)^3\cdot5^4\cdot5^{-3}\cdot7^2$